(8x^3+15x^2+6x+16)/(2x+4)

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Solution for (8x^3+15x^2+6x+16)/(2x+4) equation:


D( x )

2*x+4 = 0

2*x+4 = 0

2*x+4 = 0

2*x+4 = 0 // - 4

2*x = -4 // : 2

x = -4/2

x = -2

x in (-oo:-2) U (-2:+oo)

(8*x^3+15*x^2+6*x+16)/(2*x+4) = 0

8*x^3+15*x^2+6*x+16 = 0

8*x^3+15*x^2+6*x+16 = 0

{ 1, -1, 2, -2, 4, -4, 8, -8, 16, -16 }

1

x = 1

8*x^3+15*x^2+6*x+16 = 45

1

-1

x = -1

8*x^3+15*x^2+6*x+16 = 17

-1

2

x = 2

8*x^3+15*x^2+6*x+16 = 152

2

-2

x = -2

8*x^3+15*x^2+6*x+16 = 0

-2

x+2

8*x^2-x+8

8*x^3+15*x^2+6*x+16

x+2

-8*x^3-16*x^2

6*x-x^2+16

x^2+2*x

8*x+16

-8*x-16

0

8*x^2-x+8 = 0

DELTA = (-1)^2-(4*8*8)

DELTA = -255

DELTA < 0

x in { -2}

x+2 = 0

(x+2)/(2*x+4) = 0

x+2 = 0 // - 2

x = -2

x in { -2}

x belongs to the empty set

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